Q126IP Connectivity
An engineer must configure a `/30` subnet between two routers. Which usable IP address and subnet mask combination satisfies this requirement?
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Discussion · 23
63
answer is D. The up in A is a broadcast
32
Wait? What? Did you check the subnet mask? 225.255.255.252?
8
There is a typo in D; it should be 255.255.255.252.
That said, it's the correct answer.
4
Right, A is the broadcast address - it is explained in better detail here:
3
thats a typo
2
The answer is A. Yes it it a board cast address but it’s also a point to point link, which doesn’t need to use the broadcast IP. So we can assign it to a device instead. Plus the scenario doesn’t mention using public IP addresses go a routers to communicate. It’s could be a vpn connection for all we know.
2
Ohh another thing. Only switches broadcast and routers drop broadcast traffic by default. So all the broadcast discussion is non-sense.
C 2
Selected Answer: C
Answer D is not good. You have subnetmask 225.255.255.252. Why on first you have 225?
D 2
Selected Answer: D
ChatGpt said A then on it's own fixed itself while it was breaking it down.
A 2
Selected Answer: A
D is incorrect because subnet is wrong
1
Agree! No broadcast in P2P. A is correct.
1
A is the answer
D 1
Selected Answer: D
D is the answer. The first subnet of 209.165.201.x / 30, is 209.165.201.0-209.165.201.3. Hence, 209.175.201.2 is a host in this range.
D 1
Selected Answer: D
NONE of the options are fully correct — but if option A had used 10.2.1.1 or 10.2.1.2 instead of .3, it would be right and if Option D had used a correct subnet mask (255.255.255.252), it would be correct too.
D 1
Selected Answer: D
d is correct
D 1
Selected Answer: D
D is correct, A it is a broadcast address which makes it unusable, B & C are not point to point subnets, they have 6 usable IPs per subnet.
D 1
Selected Answer: D
The subnet mask of D thst is wrong
D 1
Selected Answer: D
D is the correct answer
A 1
Selected Answer: A
There is no correct answer. A is the broadcast address. The subnet mask is wrong because it starts with 225 instead of 255. A will be accurate if the address was 10.2.1.1 or 10.2.1.2 (network 10.2.1.0 and broadcast 10.2.1.3
1
No D is the correct answer with the correct mask
D 1
Selected Answer: D
B and C are bad answers. A is a broadcasdt.
A 1
Selected Answer: A
Correct answer is A.
D 1
Selected Answer: D
D. Correct. a /30 (255.255.255.252) has a block size of 4 and only two useable valid hosts addresses. So, a subnet 0 will have .1 and .2 valid hosts addresses, with broadcast address of .3